Forum #18 - Topic #113 - Message List

Hello,

I have two questions about the way to use shooting star in some circumstances.

Suppose you have a checkpoint consisting of 4 edges ("a","b","c","d") intersecting at the (same) vertex 0 as illustrated below:

b

|

--c---0---d--

|

a

The traffic flow through "a" and "b" is more important than through edges "c" and "d". (Every edge can be visited in both directions.)

At the vertex 0, there is a traffic light with an average waiting time of 2 minutes for edges "c" and "d" and of 1 minute for edges "a" and "b". From edge "a" you cannot drive to edge "c" and from edge "b" you cannot drive to edge "d".

In this case, we have:

1°) cost(a,c) = cost(b,d) = infinity

2°) cost(a,d) = cost(a,b) = 1

3°) cost(b,c) = cost(b,a) = 1

4°) cost(c,a) = cost(c,b) = cost(c,d) = 2

5°) cost(d,a) = cost(d,b) = cost(d,c) = 2

My two questions are:

==============

1°) The "rule" and "to_cost" columns for edge "c" would be:

gid | to_cost | rule

---------------------------

c | 2 | a,b,d

Is that correct ?

2°) What would be the "rule" and "to_cost" values for edge "a", since there are two different costs: cost(a,c)<>cost(a,d) ?

Many thanks in advance for your answer!